In this diagram, it shows that the Lg wire is connected to a diode, that comes from switched +12v, that goes to the ECU

 

 

In Numbchux diagram from his writeup, it shows the Lg wire is connected straight from switched +12v to the Ign relay, and not to the ECU at all:

 

 

I guess my question is, can I just attach the Lg wire from the Ign relay to switched +12v, or do I need to splice switched +12v between the Ign relay to the ECU? Is F47 pin 5 (or d5) used on an EJ swap at all?

 

Thank you,

-Jason

that wire is for the self-shutoff control, which means the ECU can control the ignition relay.

 

the diagram that I drew up is a simpler way to do it. I prefer to do it the other way, using the diode. But either way will work fine.

I'll stick with your diagram then, since I already cut out the diode. Thanks for your help Numbchux!

 

-Jason